Free module bases¶
The class FreeModuleBasis implements bases on a free module
of
finite rank over a commutative ring,
while the class FreeModuleCoBasis implements the dual bases (i.e.
bases of the dual module
).
AUTHORS:
- Eric Gourgoulhon, Michal Bejger (2014-2015): initial version
REFERENCES:
- Chap. 10 of R. Godement : Algebra, Hermann (Paris) / Houghton Mifflin (Boston) (1968)
- Chap. 3 of S. Lang : Algebra, 3rd ed., Springer (New York) (2002)
-
class
sage.tensor.modules.free_module_basis.Basis_abstract(fmodule, symbol, latex_symbol, latex_name)¶ Bases:
sage.structure.unique_representation.UniqueRepresentation,sage.structure.sage_object.SageObjectAbstract base class for (dual) bases of free modules.
-
free_module()¶ Return the free module of
self.EXAMPLES:
sage: M = FiniteRankFreeModule(QQ, 2, name='M', start_index=1) sage: e = M.basis('e') sage: e.free_module() is M True
-
-
class
sage.tensor.modules.free_module_basis.FreeModuleBasis(fmodule, symbol, latex_symbol=None)¶ Bases:
sage.tensor.modules.free_module_basis.Basis_abstractBasis of a free module over a commutative ring
.INPUT:
fmodule– free module
(as an instance of
FiniteRankFreeModule)symbol– string; a letter (of a few letters) to denote a generic element of the basislatex_symbol– (default:None) string; symbol to denote a generic element of the basis; ifNone, the value ofsymbolis used
EXAMPLES:
A basis on a rank-3 free module over
:sage: M0 = FiniteRankFreeModule(ZZ, 3, name='M_0') sage: from sage.tensor.modules.free_module_basis import FreeModuleBasis sage: e = FreeModuleBasis(M0, 'e') ; e Basis (e_0,e_1,e_2) on the Rank-3 free module M_0 over the Integer Ring
Instead of importing FreeModuleBasis in the global name space, it is recommended to use the module’s method
basis():sage: M = FiniteRankFreeModule(ZZ, 3, name='M') sage: e = M.basis('e') ; e Basis (e_0,e_1,e_2) on the Rank-3 free module M over the Integer Ring
The individual elements constituting the basis are accessed via the square bracket operator:
sage: e[0] Element e_0 of the Rank-3 free module M over the Integer Ring sage: e[0] in M True
The LaTeX symbol can be set explicitely, as the second argument of
basis():sage: latex(e) \left(e_0,e_1,e_2\right) sage: eps = M.basis('eps', r'\epsilon') ; eps Basis (eps_0,eps_1,eps_2) on the Rank-3 free module M over the Integer Ring sage: latex(eps) \left(\epsilon_0,\epsilon_1,\epsilon_2\right)
The individual elements of the basis are labelled according the parameter
start_indexprovided at the free module construction:sage: M = FiniteRankFreeModule(ZZ, 3, name='M', start_index=1) sage: e = M.basis('e') ; e Basis (e_1,e_2,e_3) on the Rank-3 free module M over the Integer Ring sage: e[1] Element e_1 of the Rank-3 free module M over the Integer Ring
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dual_basis()¶ Return the basis dual to
self.OUTPUT:
- instance of
FreeModuleCoBasisrepresenting the dual ofself
EXAMPLES:
Dual basis on a rank-3 free module:
sage: M = FiniteRankFreeModule(ZZ, 3, name='M', start_index=1) sage: e = M.basis('e') ; e Basis (e_1,e_2,e_3) on the Rank-3 free module M over the Integer Ring sage: f = e.dual_basis() ; f Dual basis (e^1,e^2,e^3) on the Rank-3 free module M over the Integer Ring
Let us check that the elements of f are elements of the dual of M:
sage: f[1] in M.dual() True sage: f[1] Linear form e^1 on the Rank-3 free module M over the Integer Ring
and that f is indeed the dual of e:
sage: f[1](e[1]), f[1](e[2]), f[1](e[3]) (1, 0, 0) sage: f[2](e[1]), f[2](e[2]), f[2](e[3]) (0, 1, 0) sage: f[3](e[1]), f[3](e[2]), f[3](e[3]) (0, 0, 1)
- instance of
-
new_basis(change_of_basis, symbol, latex_symbol=None)¶ Define a new module basis from
self.The new basis is defined by means of a module automorphism.
INPUT:
change_of_basis– instance ofFreeModuleAutomorphismdescribing the automorphism
that relates the current basis
(described by self) to the new basis
according
to 
symbol– string; a letter (of a few letters) to denote a generic element of the basislatex_symbol– (default:None) string; symbol to denote a generic element of the basis; ifNone, the value ofsymbolis used
OUTPUT:
- the new basis
, as an instance of FreeModuleBasis
EXAMPLES:
Change of basis on a vector space of dimension 2:
sage: M = FiniteRankFreeModule(QQ, 2, name='M', start_index=1) sage: e = M.basis('e') sage: a = M.automorphism() sage: a[:] = [[1, 2], [-1, 3]] sage: f = e.new_basis(a, 'f') ; f Basis (f_1,f_2) on the 2-dimensional vector space M over the Rational Field sage: f[1].display() f_1 = e_1 - e_2 sage: f[2].display() f_2 = 2 e_1 + 3 e_2 sage: e[1].display(f) e_1 = 3/5 f_1 + 1/5 f_2 sage: e[2].display(f) e_2 = -2/5 f_1 + 1/5 f_2
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class
sage.tensor.modules.free_module_basis.FreeModuleCoBasis(basis, symbol, latex_symbol=None)¶ Bases:
sage.tensor.modules.free_module_basis.Basis_abstractDual basis of a free module over a commutative ring.
INPUT:
basis– basis of a free module
of which selfis the dual (must be an instance ofFreeModuleBasis)symbol– a letter (of a few letters) to denote a generic element of the cobasislatex_symbol– (default:None) symbol to denote a generic element of the cobasis; ifNone, the value ofsymbolis used
EXAMPLES:
Dual basis on a rank-3 free module:
sage: M = FiniteRankFreeModule(ZZ, 3, name='M', start_index=1) sage: e = M.basis('e') ; e Basis (e_1,e_2,e_3) on the Rank-3 free module M over the Integer Ring sage: from sage.tensor.modules.free_module_basis import FreeModuleCoBasis sage: f = FreeModuleCoBasis(e, 'f') ; f Dual basis (f^1,f^2,f^3) on the Rank-3 free module M over the Integer Ring
Let us check that the elements of
fare in the dual ofM:sage: f[1] in M.dual() True sage: f[1] Linear form f^1 on the Rank-3 free module M over the Integer Ring
and that
fis indeed the dual ofe:sage: f[1](e[1]), f[1](e[2]), f[1](e[3]) (1, 0, 0) sage: f[2](e[1]), f[2](e[2]), f[2](e[3]) (0, 1, 0) sage: f[3](e[1]), f[3](e[2]), f[3](e[3]) (0, 0, 1)
